00:01
Hello students, according to the given question it was given the x and y joint data so that contains y values 1, 2, 3 and x values are 1, 2, 3.
00:16
So here it is 0 .32, 0 .06, 0 .02, 0 .03, 0 .24, 0 .03, 0 .01, 0 .02, 0 .27.
00:36
So here the total values are 0 .36, 0 .32, 0 .32 and here the column totals will be 0 .4, 0 .3, 0 .3 and 1.
00:59
So this is the table given in the a bit probability of x is equal to 2 and y is equal to 2 that will be so from above table it is 0 .24 in the b bit probability of x give x equal to 2 given y is equal to 2 that is equal to probability of x is equal to 2 and y is equal to 2 divided by probability of y is equal to 2.
01:30
So from above table the data is 0 .24 by 0 .03 plus 0 .24 plus 0 .03.
01:39
So which is equal to 0 .8 in the c bit expectation of x is equal to summation x into probability of x is equal to x.
01:52
So then which is equal to 1 into 0 .36 plus 2 into 0 .32 plus 3 into 0 .32.
02:02
So which is equal to 1 .96.
02:05
In the d bit expectation of y is equal to summation y into probability of y is equal to y...