00:01
Hello, let's look at the question.
00:02
We have been given to consider the equation z to the power 11 equals to minus 1 plus i.
00:08
We have to find the value of z with satisfied equation.
00:11
So as we are given this, now we can write minus 1 minus i and put 2 under root 2 cos minus 3 pi by 4 plus i sin minus 3 pi by 4.
00:33
So our z11 will be under root 2 cos minus 3 pi by 4 plus i sin minus 3 pi by 4 under root 2 cos minus 3 pi by 4 plus 2 k pi plus i sin minus 3 pi by 4 plus 2 k pi where our k is equal to 0 plus minus 1 plus minus 2 plus minus 3.
01:11
Now our z is equal to under root 2 cos minus 3 pi by 4 plus 2 k pi plus i sin minus 3 pi by 4 plus 2 k pi minus sorry plus 1 by 11.
01:34
Our k is 0, 1, 2 up to 10.
01:41
Then our z is equal to under root 2 1 by 11 cos minus 3 pi by 4 plus 2 k pi by 11 plus i sin minus 3 pi by 4 plus 2 k pi by 11.
02:06
Further as we know our k is here 0, 1, 2 up to 10...