Question

12. Consider the equilibrium reaction between O2 and O3 (ozone): 3O2 (g) \leftrightarrow 2O3; Kc = 6.3 x 10^{-58} (at 25 °C) What is the volume of air (21 % O2 by volume) at 1.0 atm and 25 °C that you would predict to contain one molecule of ozone at equilibrium, if the only source of O3 were its formation from O2? (The molar volume of air at 1 atm and 25 °C is 24.45 L).

          12.
Consider the equilibrium reaction between O2 and O3 (ozone):
3O2 (g) \leftrightarrow 2O3; Kc = 6.3 x 10^{-58} (at 25 °C)
What is the volume of air (21 % O2 by volume) at 1.0 atm and 25 °C that you would predict to
contain one molecule of ozone at equilibrium, if the only source of O3 were its formation from O2?
(The molar volume of air at 1 atm and 25 °C is 24.45 L).

12.
Consider the equilibrium reaction between O2 and O3 (ozone):
3O2 (g) ↔2O3; Kc = 6.3 x 10^-58 (at 25 °C)
What is the volume of air (21 % O2 by volume) at 1.0 atm and 25 °C that you would predict to
contain one molecule of ozone at equilibrium, if the only source of O3 were its formation from O2?
(The molar volume of air at 1 atm and 25 °C is 24.45 L).

Added by Laura H.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Dinesh Singh

02/20/2022

Step 1

Since the volume of air is 24.45 L and the percentage of O3 is 21%, the volume of O3 in the air is 24.45 L * 0.21 = 5.14 L. Assuming all the O3 is formed from O2, the initial concentration of O2 is 24.45 L - 5.14 L = 19.31 L. Show more…

Show all steps

Thanks for your feedback!

Consider the equilibrium reaction between O_(2) and O_(3) (ozone): 3O_(2)(g)⇄2O_(3);,K_(c)=6.3 imes 10^(-58), (at 25deg C ) What is the volume of air by volume) at 1.0atm and 25deg C that you would predict to contain one molecule of ozone at equilibrium, if the only source of O_(3) were its formation from O_(2) ? (The molar volume of air at 1atm and 25deg C is 24.45L ). 12 Consider the equilibrium reaction between Oz and O (ozone) 3Og2O3;Kc=6.3x10-58 at25C What is the volume of air (21 % Oz by volume) at 1.0 atm and 25 C that you would predict to (The molar volume of air at 1 atm and 25 C is 24.45 L).