00:01
Hello everyone.
00:02
So for this question we have been given the mass of carbon as 11 .1 grams mass of water is given as 2 .45 grams, mass of carbon monoxide is given as 15 .3 grams.
00:11
And we have the mass of hydrogen as 7 .55 grams.
00:14
We also have the volume of the container in which all of these reactants are present.
00:18
The volume is 2 .5 liters.
00:20
What we need to find is the qc, that is the reaction coefficient of this reaction.
00:25
So the reaction coefficient for this reaction will be equal to the product of the concentration of the products, that will be equal to the concentration of carbon monoxide multiplied by the concentration of this hydrogen divided by the concentration of water.
00:43
Now we haven't taken this carbon in this qc, that is the reaction coefficient, because carbon is present in solid form and the active mass of solid or liquid is taken as one.
00:54
Now to find the qc, that is the reaction coefficient of this reaction, we also need to find the concentration of the species that are present in the equation.
01:03
So to find this, we will use the formula formularity, and that is equals to given mass divided by the molar mass multiplied by 1, divide by the volumes in liters...