00:01
Hi students in this question, it is given that a traffic light is being suspended with the help of two cables which are making a particular angle of 45 degree each with the horizontal.
00:10
Now since these two angles are 45 degree, these angles can be also considered as 45 degree.
00:17
Now here it is given that this traffic light system is having a weight w to be equal to 60 newton, where we know that weight w will be equal to the product of mass into acceleration due to gravity g.
00:29
And the value of acceleration due to gravity g is taken to be 9 .8 meter per second square.
00:35
The opposite in the value of w and g in this equation, we get the mass of the system m to be equal to 6 .12 kilogram.
00:43
Now based on the angle 45 degree, the weight can be resolved into two components for both left hand side as well as right hand side.
00:50
And for right hand side, it can be divided into a value of w coarse 45 degree as well as a value of w sine, 45 degree.
01:00
On the other hand, for the left hand side it can be resolved as minus w cos 45 degree as well as a value of w sign 45 degree.
01:09
Now in the first part of the question we are asked to find out the resultant force which is acting for this light system which is taken as capillator f.
01:17
And here we can say that the horizontal force acting here can be taken as fx which is equal to minus w course 45 degree plus a value of w into course 440...