Consider the figure below. (Let R1 = 1.60 Ω,
and R2 = 1.80 Ω.)
A circuit is comprised of two adjacent square loops that share a
side such that the top side of the bottom loop is also the bottom
side of the top loop.
The bottom side of the bottom loop contains a 5.00 Ω
resistor.
The left side of the bottom loop contains a 12.0 V battery
oriented such that the positive terminal is on the top and the
negative is on the bottom.
The right side of the bottom loop contains a resistor
R2 and a current I2 that
points downwards.
The right side of the top loop contains a 4.00 Ω resistor and a
current I1 that points downwards.
The top side of the top loop contains a resistor
R1.
The left side of the top loop contains a 24.0 V battery oriented
such that the positive terminal is on the top and the negative is
on the bottom.
The shared side contains a 3.00 Ω resistor and a current
I3 that points to the left.
(a) Can the circuit shown in the figure above be reduced to a
single resistor connected to a battery?
Yes
No
There is not enough information.
Explain.
(b) Calculate the current I1.
(c) Calculate the current I2.
(d) Calculate the current I3.