Consider the following. $10^{-x} = 121$ (a) Find the exact solution of the exponential equation in terms of logarithms. x = -2\log_{10}(11) (b) Use a calculator to find an approximation to the solution rounded to six decimal places. x = -2.08279
Added by Linda D.
Close
Step 1
Step 1: To find the exact solution of the exponential equation 2log10(11), we can use the property of logarithms that states log_b(a) = c is equivalent to b^c = a. Show more…
Show all steps
Your feedback will help us improve your experience
Kevin Lu and 98 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Exponential Equations (a) Find the exact solution of the exponential equation in terms of logarithms. (b) Use a calculator to find an approximation to the solution rounded to six decimal places. $$10^{1-x}=6^{x}$$
Exponential and Logarithmic Functions
Exponential and Logarithmic Equations
? Exponential Equations (a) Find the exact solution of the exponential equation in terms of logarithms. (b) Use a calculator to find an approximation to the solution rounded to six decimal places. $$ 10^{1-x}=6^{x} $$
Exponential Equations (a) Find the exact solution of the exponential equation in terms of logarithms. (b) Use a calculator to find an approximation to the solution rounded to six decimal places. $$3 e^{x}=10$$
Recommended Textbooks
Precalculus with Limits
Precalculus
Transcript
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD