Consider the following balanced reaction. What mass (in g) of CO2 can be formed from 739 mg of O2? Assume that there is excess C3H7SH present. C3H7SH(l) + 6 O2(g) → 3 CO2(g) + SO2(g) + 4 H2O(g)
Added by Travis S.
Step 1
First, we need to find the moles of O2. We know that the molar mass of O2 is 32 g/mol. So, we can convert the mass of O2 to moles: moles of O2 = (739 mg O2) * (1 g / 1000 mg) * (1 mol / 32 g) = 0.02309375 mol O2 Show more…
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