consider the following contingency table b bc a 26 26 ac 20 28 a convert the contingency table i

a. To convert the contingency table into a joint probability table, we need to divide each cell

Question

Consider the following contingency table. B Bc Total A 26 26 Ac 20 28 Total 46 54 a. Convert the contingency table into a joint probability table. (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.) B Bc Total A 0.5652 0.5652 Ac 0.4348 0.4348 Total 1.0000 1.0000 b. What is the probability that A occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.) P(A) = 0.5652 c. What is the probability that A and B occur? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.) P(A ∩ B) = 0.5652 d. Given that B has occurred, what is the probability that A occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.) P(A | B) = 0.5652 e. Given that Ac has occurred, what is the probability that B occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.) P(B | Ac) = 0.5185 f. Are A and B mutually exclusive events? No because P(A ∩ B) ≠ 0. g. Are A and B independent events? No because P(A | B) ≠ P(A).

          Consider the following contingency table.

        B   Bc   Total
A       26   26
Ac     20   28
Total  46   54

a. Convert the contingency table into a joint probability table. (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)

        B       Bc      Total
A       0.5652  0.5652
Ac     0.4348  0.4348
Total  1.0000  1.0000

b. What is the probability that A occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)

    P(A) = 0.5652

c. What is the probability that A and B occur? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)

    P(A ∩ B) = 0.5652

d. Given that B has occurred, what is the probability that A occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)

    P(A | B) = 0.5652

e. Given that Ac has occurred, what is the probability that B occurs? (Round intermediate calculations to at least 4 decimal places and final answer to 4 decimal places.)

    P(B | Ac) = 0.5185

f. Are A and B mutually exclusive events?

    No because P(A ∩ B) ≠ 0.

g. Are A and B independent events?

    No because P(A | B) ≠ P(A).

Added by Bryan D.

Question

Please give Ace some feedback