Consider the following data drawn independently from normally distributed populations: (You may find it useful to reference the appropriate table: z table or t table) \bar{x}_1 = -13.1 \bar{x}_2 = -16.2 s_1^2 = 8.9 s_2^2 = 9.2 n_1 = 25 n_2 = 30 a. Construct the 95% confidence interval for the difference between the population means. Assume the population variances are unknown but equal. (Round all intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.) Confidence interval is to
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1 - Sample 1 standard deviation (\(s_1\)) = 8.9 - Sample 1 size (\(n_1\)) = 25 - Sample 2 mean (\(\bar{x}_2\)) = -16.2 - Sample 2 standard deviation (\(s_2\)) = 9.2 - Sample 2 size (\(n_2\)) = 30 - Confidence level = 95% Show more…
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