00:01
So this question to predict the type of bond, we need to calculate the electronegativity difference.
00:12
So a difference of 0 .2 would be a covalent bond.
00:18
Difference of 0 .3 to 1 .6 would be a polar covalent bonds.
00:26
And difference of 1 .6 to 4 .0 would be an ionic bond.
00:31
So we need our electronegativity table for a.
00:38
Between rubidium and chlorine.
00:41
Rubidium has electronegativity difference here.
00:46
Chlorine is 3 .16, and rubidium is 0 .82.
00:54
So electronegativity difference here.
00:58
3 .16 minus point 82.
01:00
Now we can have slightly different electronegativity tables, so numbers can be slightly different.
01:05
2 .34, which means that this is ionic.
01:10
For b, we've got sulfur and sulfur.
01:20
Electritoritivity difference here is 2 .58 minus 2 .58, which is 0, which means that this is a covalent bond between sulfur and sulfur.
01:32
For c, between barium and sulfur.
01:35
For c, between barium and sulfur.
01:40
So electronegativity difference here.
01:42
Sulfur is 2 .58 and barium is 0 .89.
01:50
So this would be 2 .58 minus 0 .89.
01:53
That would be 1 .69.
01:56
Rounds up to 1 .7 so i let's say that this would be ionic and for d between barium or sorry i got them wrong here rubidium so if c is carbon and fluorine sorry i got this wrong here let's go back carbon and fluorine electronegativity difference chlorine is 3 .98...