Consider the following equilibrium: 4HCl(g) + O2(g) ⇌ 2H2O(g) + 2Cl2(g) Kc = 357 An equilibrium mixture of the above system was found to contain the following concentrations: HCl(g) = 0.35 mol/L, O2(g) = 0.078 mol/L and H2O(g) = 1.2 mol/L. The equilibrium concentration of Cl2(g) is calculated to be Answer Question 17 mol/L Record your answer to two decimal places. Do not include units.

Name: consider the following equilibrium 4hclg o2g 2h2og 2cl2g kc 357 an equilibrium mixture of the above system was found to contain the following concentrations hclg 035 moll o2g 0078 moll and h 66024
Uploaded: 2022-04-05T04:36:29-08:00
Duration: 1 min 59 s
Channel: Ronald Prasad
Description: consider the following equilibrium 4hclg o2g 2h2og 2cl2g kc 357 an equilibrium mixture of the above system was found to contain the following concentrations hclg 035 moll o2g 0078 moll and h 66024

          Consider the following equilibrium: 4HCl(g) + O2(g) ⇌ 2H2O(g) + 2Cl2(g)     Kc = 357
An equilibrium mixture of the above system was found to contain the following concentrations: HCl(g) = 0.35 mol/L, O2(g) = 0.078 mol/L and H2O(g) = 1.2 mol/L. The equilibrium concentration of Cl2(g) is calculated to be Answer Question 17 mol/L
Record your answer to two decimal places. Do not include units.

Added by Kenneth G.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Ronald Prasad

04/05/2022

Step 1

The equilibrium expression for the reaction is: Kc = [H2O]^2 * [Cl2]^2 / [HCl]^4 * [O2] Show more…

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Consider the following equilibrium: 4HCl(g) + O2(g) ⇌ 2H2O(g) + 2Cl2(g) Kc = 357 An equilibrium mixture of the above system was found to contain the following concentrations: HCl(g) = 0.35 mol/L, O2(g) = 0.078 mol/L and H2O(g) = 1.2 mol/L. The equilibrium concentration of Cl2(g) is calculated to be Answer Question 17 mol/L Record your answer to two decimal places. Do not include units.