The PDF is given by:
$$
f(x) = \frac{1}{2}e^{-x/2}
$$
for $x > 0$. The CDF is the integral of the PDF, which gives us the probability of $P(x < x_0)$. So, we have:
$$
P(x < x_0) = \int_0^{x_0} \frac{1}{2}e^{-x/2} dx
$$
Integrating, we get:
$$
P(x < x_0) = 1 -
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