Question

f(x) = \begin{cases} 1, & x < 0\\ x^2 + 1, & 0 \le x < 1\\ -x^2 + 2x + 1, & 1 \le x < 2\\ 1, & x \ge 2 \end{cases}

          f(x) = \begin{cases} 1, & x < 0\\ x^2 + 1, & 0 \le x < 1\\ -x^2 + 2x + 1, & 1 \le x < 2\\ 1, & x \ge 2 \end{cases}

f(x) = 1, x < 0
x^2 + 1, 0 ≤x < 1
-x^2 + 2x + 1, 1 ≤x < 2
1, x ≥2

Added by Joel L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Gregory Higby

07/10/2022

Step 1

```matlab function y = f(x) if x < 0 y = 0; elseif x >= 0 && x < 1 y = x^2 + 1; elseif x >= 1 && x < 2 y = -x^2 + 2*x + 1; else y = 1; end end ``` Show more…

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