This means that we need to substitute the function \(g(x)\) into the function \(f(x)\).
So, \((f \circ g)(x) = f(g(x))\).
Substituting \(g(x) = x + 3\) into \(f(x) = \frac{1}{\sqrt{x}}\), we get:
\((f \circ g)(x) = f(x + 3) = \frac{1}{\sqrt{x + 3}}\).
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