Question

Consider the following gas phase reaction: 4HCl(g) + O2(g) -> 2Cl2(g) + 2H2O(g) What mass of chlorine can be prepared from the reaction of 400 mL of gaseous HCl, measured at STP, with excess O2, assuming that all the HCl reacts? Answer options: 190 g 0.634 g 0.686 g 0.951 g 1.42 g

Name: consider the following gas phase reaction 4hclg o2g 2cl2g 2h2og what mass of chlorine can be prepared from the reaction of 400 ml of gaseous hcl measured at stp with excess o2 assuming that 31705
Uploaded: 2021-12-23T01:31:21-08:00
Duration: 4 min 12 s
Channel: Paul Gabriel
Description: consider the following gas phase reaction 4hclg o2g 2cl2g 2h2og what mass of chlorine can be prepared from the reaction of 400 ml of gaseous hcl measured at stp with excess o2 assuming that 31705

          Consider the following gas phase reaction:
4HCl(g) + O2(g) -> 2Cl2(g) + 2H2O(g)

What mass of chlorine can be prepared from the reaction of 400 mL of gaseous HCl, measured at STP, with excess O2, assuming that all the HCl reacts?

Answer options:
190 g
0.634 g
0.686 g
0.951 g
1.42 g

Added by Scott V.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Paul Gabriel

12/23/2021

Step 1

Given that 1 mole of any gas at STP occupies 22.4 L, we can calculate the number of moles of HCl in 400 mL: 400 mL = 0.4 L 0.4 L / 22.4 L/mol = 0.01786 moles of HCl Show more…

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Consider the following gas phase reaction: 4HCl(g) + O2(g) -> 2Cl2(g) + 2H2O(g) What mass of chlorine can be prepared from the reaction of 400 mL of gaseous HCl, measured at STP, with excess O2, assuming that all the HCl reacts? Answer options: 190 g 0.634 g 0.686 g 0.951 g 1.42 g