00:01
Hello students, let us solve the problem step by step.
00:04
Let us calculate a1 first where we need to find the test statistics which the given data is x bar is equals to 421, n is equals to 85 and h naught which is null hypothesis is termed as mu is equals to 410 where population mean is 410 and the alternative hypothesis is mu is not equals to 410 where the population is not equals to 410 and given that standard deviation sigma is equals to 46 and x bar and n are already given.
00:47
So, let us write the test statistics for this as z is equals to x bar minus mu by sigma by root n is the standard formula for this.
01:02
So, let us substitute all the values in that which gives 421 minus 410 by 46 divided by under root 85.
01:16
Therefore, the z value is given as the test statistics is 2 .19836 and now let us go for a2 that what is the conclusion of 100 percent significance level.
01:39
So, at 100 percent significance level we generally compare the absolute value of the test statistics which is 2 .19836 with the critical value.
01:51
So, from a total test at 10 percent significance level the critical value is approximately equals to 1 .645 using a z table or a calculator and this is actually plus or minus 1 .645 it is because it is a two tailed test.
02:18
So, since the absolute value of test statistics is greater than this value the critical value which is 1 .645 we reject the null hypothesis.
02:29
Therefore, we reject the null hypothesis h naught and conclude that there is a sufficient evidence to support the alternative hypothesis h1 and in other words we can say that the population mean is not equals to 410 and at a 10 percent level of significance.
02:54
Let us go for the value a3 where we need to interpret the results for alpha is equals to 0 .10 at alpha 0 .10 which means 10 percent significance level.
03:07
We can conclude that the population mean differs from 410 because we rejected h naught null hypothesis in the favor of alternative hypothesis...