Question

Consider the following hypothesis test: $H_0: mu = 18$ $H_a: mu eq 18$ A sample of 48 provided a sample mean $ar{x} = 17$ and a sample standard deviation $s = 4.5$. If requires, round your answers to two decimal places. a. Compute the value of the test statistic. -1.54 b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value. p-value is between .10 and .20 c. At $alpha = .05$, what is your conclusion? p-value greater than 0.05, do not reject $H_0$ d. What is the rejection rule using the critical value? Reject $H_0$ if $t$ less than or equal to -2.012 or $t$ greater than or equal to 2.012 What is your conclusion? If your answer is negative, use minus "-" sign. $t = .1335$; do not reject $H_0$

          Consider the following hypothesis test:
$H_0: mu = 18$
$H_a: mu 
eq 18$
A sample of 48 provided a sample mean $ar{x} = 17$ and a sample standard deviation $s = 4.5$.
If requires, round your answers to two decimal places.
a. Compute the value of the test statistic.
-1.54
b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value.
p-value is between .10 and .20
c. At $alpha = .05$, what is your conclusion?
p-value greater than 0.05, do not reject $H_0$
d. What is the rejection rule using the critical value?
Reject $H_0$ if $t$ less than or equal to -2.012 or $t$ greater than or equal to 2.012
What is your conclusion? If your answer is negative, use minus "-" sign.
$t = .1335$; do not reject $H_0$

Consider the following hypothesis test:
H0: mu = 18
Ha: mu
eq 18
A sample of 48 provided a sample mean arx = 17 and a sample standard deviation s = 4.5.
If requires, round your answers to two decimal places.
a. Compute the value of the test statistic.
-1.54
b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value.
p-value is between .10 and .20
c. At alpha = .05, what is your conclusion?
p-value greater than 0.05, do not reject H0
d. What is the rejection rule using the critical value?
Reject H0 if t less than or equal to -2.012 or t greater than or equal to 2.012
What is your conclusion? If your answer is negative, use minus "-" sign.
t = .1335; do not reject H0

Added by Ashley G.

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