Consider the following joint distribution of X and Y. Find E[2X+3Y+5] Y = 1 | Y = 2 | Y = 3 X = 1 | .1 | .2 | 0 X = 2 | .1 | 0 | .2 X = 3 | 0 | .1 | .3 16.1 10.2 18.5 5.6 Consider the following joint distribution of X and Y. Find E[Y|X=3]. Y = 1 | Y = 2 | Y = 3 X = 1 | .1 | .2 | 0 X = 2 | .1 | 0 | .2 X = 3 | 0 | .1 | .3 1 11/4 2 15/4
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1 E[Y] = 2.3 E[2X+3Y+5] = 2*E[X] + 3*E[Y] + 5 E[2X+3Y+5] = 2*2.1 + 3*2.3 + 5 E[2X+3Y+5] = 4.2 + 6.9 + 5 E[2X+3Y+5] = 16.1 Therefore, **E[2X+3Y+5] = 16.1** Show more…
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