Question

Consider the following.\\ $\lim_{x \to 1} \frac{x - 4}{x^2 + 5x - 36}$ \\ Create a table of values for the function. (Round your answers to four decimal places.)\\ x | 0.9 | 0.99 | 0.999 | 1.001 | 1.01 | 1.1\\ f(x) | | | | | |

          Consider the following.\\
$\lim_{x \to 1} \frac{x - 4}{x^2 + 5x - 36}$ \\
Create a table of values for the function. (Round your answers to four decimal places.)\\
x | 0.9 | 0.99 | 0.999 | 1.001 | 1.01 | 1.1\\
f(x) |  |  |  |  |  |
        
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Consider the following.

limx → 1(x - 4)/(x^2 + 5x - 36) 

Create a table of values for the function. (Round your answers to four decimal places.)

x | 0.9 | 0.99 | 0.999 | 1.001 | 1.01 | 1.1

f(x) |  |  |  |  |  |

Added by Samuel P.

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Elementary and Intermediate Algebra
Elementary and Intermediate Algebra
Alan S. Tussy, R. David Gustafson 5th Edition
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Consider the following. lim_(x->1)(x-4)/(x^(2)+5x-36) Create a table of values for the function. (Round your answers to four decimal places.) able[[x,0.9,0.99,0.999,1.001,1.01,1.1],[f(x),,,,,,]] Consider the following. lim x-4 Create a table of values for the function.(Round your answers to four decimal places.) 0.9 0.99 666'0 1.001 1.01 1.1
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Transcript

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00:01 Here we have been given a function fx which is just equal to 6 e raised to power x minus 6 upon x and we have to find the function when limit x approaches 0, 6 e raised to power x minus 6 upon x.
00:26 We have to find this.
00:27 So now here we have also been given some values of x in the table.
00:32 So here firstly the f of minus 0 .1 we can take will be just equal to 6 e raised to power minus 0 .1, 0 .1 minus 6 upon minus 0 .1 and if we use the values it will just be equal to 5 .709 or f of minus 0 .01 this equation just becomes 6 e raised to power minus 0 .01 minus 6 upon negative of 0 .01 which will just be equal to 5 .97.
01:15 Further we can put the value of f of negative 0 .001 which is equal to 6 e raised to power minus 0 .001 minus 6 upon minus 0 .001.
01:37 As you can see we are putting the value 0 .1, 0 .01, 0 .0001...
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