00:01
The compound given to us is brf5.
00:05
For this compound, louis structure will be like.
00:12
This structure is br5 fluorine atom attached with bromine.
00:26
So this is 1 fluorine, 2, 3, 4 and 5.
00:42
5 fluoridum and here 2 electrons are present.
00:47
If you see the bond length between br and f over here it will be 177 .4 picometer and here in this case br and f having the bond length 168 .9 picometers and the bond length of these the angle between f, br and f is 84 .8 degrees.
01:20
We also can draw the lewis dot structure and that will be like five fluorine atoms here make bond with bromine fluorine fluorine fluorine and two electron are remaining.
01:44
As we know that chlorine having valence is 7, so here three loan pairs are present on fluorine atom.
01:54
1, 2, 3 and here each fluorine atom are having 3 pair of the electrons.
02:04
This is our louis structure.
02:08
This is the dog structure.
02:10
This is the bond structure of the brf.
02:14
5.
02:16
In the case of vra5, first we are going to calculate number of balance electrons.
02:29
In the case of bromine, the valence electron is 7 electrons and 5 fluorine atoms having the valency 5 multiplied with 7 which is 35 electrons.
02:45
Hence the 2.
02:46
Total valence electron is 42 electron.
02:50
This is the number of valence electron in the case of the area.
02:55
And area of electron density around central atom.
03:09
Over here the central atom is bromine.
03:14
Bromine is having five fluorin atom if, f, f, f...