Consider the following random sample from a normal population: 14, 10, 13, 16, 12, 18, 15, and 11. What is the 95% confidence interval for the population variance? a) 1.76 to 5.43 b) 2.86 to 24.53 c) 1.12 to 5.69 d) 6.54 to 38.82 e) 3.11 to 29.51
Added by Gina E.
Step 1
First, we need to find the sample mean (x̄) and the sample variance (s²). x̄ = (14 + 10 + 13 + 16 + 12 + 18 + 15 + 11) / 8 = 99 / 8 = 12.375 Now, we need to find the deviations from the mean and square them: (14 - 12.375)² = 2.640625 (10 - 12.375)² = Show more…
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Construct a 95% confidence interval for μ 1 - μ 2. Two samples are randomly selected from normal populations. The sample statistics are given below. n 1 = 8 n 2 = 7 1 = 4.1 2 = 5.5 s 1 = 0.76 s 2 = 2.51 Answers: a: (-1.132, 1.543) b. (2.112, 2.113) c. (-3.813, 1.013) d. (-3.813, 1.013)
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