00:01
So, the reaction that would be taking place is 2so2 solid reacts with o2 gas and this would result in the formation of 2so3 gas.
00:10
Now, first of all we will calculate the moles of oxygen.
00:16
So, it would be equal to the given mass of o2 which is 1 .5 grams divided by the molar mass of oxygen which is 32 gram per mole.
00:25
And from here the moles comes out to be equal to 0 .046875 moles.
00:32
Now similarly we will calculate the moles of another reactant which is so2.
00:37
So it would be equal to the given mass which is 3 gram divided by the molar mass of so2 which is 64 gram per mole and from here the moles comes out to be equal to 0 .046875 moles.
00:51
Now if we see the reactions tisiometry that is the coefficient written in front of the reactants and products.
00:57
So it says that 2 moles of so2 react with 1 mole of o2 and it result into the formation of 2 moles of so3.
01:17
Now from here we can simply say that from here 1 mole of so2 react with if we have the reaction react with 1 by 2 mole of o2.
01:36
Or from here we can say 0 .046875 moles of so2 react with basically we are calculating this much amount of so2 will be reacting with how much of the o2.
01:54
So it will react with is equal to 1 multiplied 1 divided by 2 multiplied by 0 .046875 and that would be equal to 0 .0234375 moles...