00:01
We take note that when the reaction is reversed, let's say a or let's say let's make it x forming y with an equilibrium constant of let's say k1, if it's reversed, let's just say that we have y forming x, the equilibrium constant for this is k2 and is related to k1 as 1 divided by k1.
00:32
So in other words, if we reverse the chemical equilibrium equation, then the equilibrium constant will be or that the reciprocal of the equilibrium constant will be taken.
00:41
Also, if we add two equations, let's say we have a or let's use still x, x forming y, then add it with c forming m with equilibrium constants k1 and k2 respectively.
01:03
If we add them together, such that we have x plus c forming y plus m, then the equilibrium constant for this will just be the product of the equilibrium constants of the two equations we added to form it.
01:17
So given here in this problem, we have a to form b with an equilibrium constant k1 of 6 .54 and that we also have a forming c with an equilibrium constant k2 of 2.
01:34
We wish to find the equilibrium constant of c forming b.
01:39
So find equilibrium constant for c forming b.
01:42
So to get this, we first take the reverse of the second equation.
01:53
So let's say equation 2.
01:56
So in doing that, gives us c forming a...