00:01
We are given this particular circuit and we want to solve using kercholf's rules to find what is the voltage across each resistor as well as the power that's being supplied.
00:18
So first off, we need to identify why is the direction of the current.
00:25
In this case because v2 is greater than v1, it's likely that you have the current that is going according to v2.
00:33
Direction so that will be in this particular direction.
00:41
So this is the current that we set.
00:46
And from this current we're going to use the entire loop to first, well, identify what is the total potential across a single loop.
01:04
Now from kerchow's rules, that must be equals to 0.
01:07
Right when we go in an entire loop so we started from over here just before the battery here and move across the battery in the direction of the current we'll move in a anti -clockwise manner so first off we have the potential or emf from our battery which we add because it's in the direction from minus to class, then we have a potential drop due to the resistor, r3.
01:55
So there's i -r3, where i is the overall current for our system.
02:03
Then we have another potential drop across r2 and a potential drop at r1.
02:16
And for this battery v1 we are moving from plus to the minus terminal so we have to subtract away this potential which is v1 move on to r5 and finally r4 and this must be equals to zero since this is a complete loop now the unknown that we have in this equation there's only one unknown which is i and we already have all the relevant values right or in this figure so what we do we just want to find i factorize out i after bringing all the terms with i to the right -hand side i have our 1 plus r2 plus r3 basically the total resistance of the circuit is equivalent to v2 minus v1.
03:27
So i would be just equals to 24 minus 12 divided by the total resistance which is 10 plus 10, 20, 30, 40, 60 so that's 60 kilo -ooms so there'll be 2 .0 times 10 to power minus 4...