00:01
Alright, so we have these two systems right here, 3x -2y equals negative 5, and negative 6x plus 4y equals 10.
00:08
And we have this point, negative 1 comma 1, and we want to see if it's on both lines in this system by just substituting it in.
00:17
So this is an x coordinate, the negative 1 is, and the 1 is a y coordinate.
00:22
So i'm going to put negative 1 in for x in both places, and i'm going to put 1 in for y in both equations, and i'm going to see if it's still true.
00:33
So 3 times negative 1 minus 2 times 1, does that equal negative 5? well this comes out to be negative 3, this is negative 2, this is negative 5, and we see that negative 5 does equal negative 5.
00:52
Yes.
00:52
So that means negative 1 comma 1, this point, is on the graph, 3x minus 2y equals negative 5.
01:09
Now i'm going to do the same thing over here.
01:11
Negative 6 times negative 1 plus 4 times 1, does that equal 10? put a little question mark because i don't know.
01:20
This comes out to be 6, this comes out to be 4, and 6 plus 4 is 10...