00:01
So, here we will write controllable canonical form that is y of z divided by x of z or z that is equal to beta, say z to the power n, beta1, z to the power n -1 in the same way is up to beta to the power n divided by z to the power n plus z to the power n -1 plus this is alpha1 up to alpha n, okay.
00:49
So, here this a will be equal to 0, 1, 0 up to 0, 0, 0, 1 up to 0.
01:05
So, this will continue up to this minus alpha n minus of alpha n -1, this is up to alpha1, okay.
01:14
So, here this b value which will be 0, 0, 1, 1, 0, 1, okay.
01:21
And the c value which will come as beta n minus of alpha n beta 0, so after that beta, so here it is beta n -1 minus of alpha n -1 beta 0, this is up to beta1 minus of alpha1 beta 0 and the d value is simply beta 0 only, okay.
01:50
So, now we have to find out the y of z divided by x of z, so that is equal to or we can say this is a u, okay, as per the question we will take it as a u.
02:02
So, this is equal to z to the power minus 1 plus 2z to the power minus 2 divided by 1 plus 4z to the power minus 1 plus 3z to the power minus 2 is equal to minus z z plus 2 divided by z square plus 4z plus 3, okay...