00:01
Hello students, so we know that when ethyl bromide reacts with potassium cyanide, it forms ethyl cyanide as a major product and ch3ch2nc as a minor product.
00:21
So we have to draw the lewis structure of cn-.
00:26
So firstly we will see the total number of valence electrons of cn-.
00:32
So here the valence electron of carbon is 4, that of nitrogen is 5 and we have an extra minus, so plus 1 that is 10 electrons.
00:42
So let us draw the structure starting, so we have carbon and nitrogen, so we will firstly place 2 electrons in between them as, so 2 electrons are gone, so there are 8 electrons left and we will use those 8 electrons to firstly fill the octet of nitrogen.
01:07
So we will, so we have used up 8 electrons and we will fill the rest of 6 electrons and we will fill the rest of the 2 electrons in carbon.
01:20
Now you can see the nitrogen, the octet is satisfied but for carbon only 4 electrons are there.
01:27
So what we will do is, we will simply shift these 2 electron pairs to form something like this and so now you can see that carbon has 8 electrons and nitrogen has 8 electrons, so they are both stable and the negative charge will be something like this, we will put it here...