Consider the following circuit, where R = 6 \Omega, L? = 1 H, L? = 0.3 H. Derive the transfer function, H(s) = V?(s)/V?(s). Assume no initial energy. Vi + - L? R L? + V? a) \frac{0.2s}{s+2} b) \frac{0.5s}{s^2+1} c) \frac{0.4s^2}{s+2} d) \frac{0.2}{s+1} e) None of the above
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We can start by applying Kirchhoff's voltage law (KVL) to the loop: V(s) = I(s) * (R + sL) + I(s) * sL Show more…
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