00:01
For this question, we're given the function g of x is equal to co -secend of x, an interval from pi over 3, which is less than equal to x, which is less than equal to pi over 3.
00:10
And we're asked to find absolute extreme values, which we know are in absolute maximums and minimums.
00:15
So to start off with, let's find our critical numbers, so we know g prime of x equal to negative cotangent x, co -secant of x.
00:24
So we know that no cotangent of x, cosecant of x, is equal to 0, when x is equal to pi over 2.
00:34
And other stuff, too, but that's the only part where it's on this interval.
00:40
So we have, let's see, so now we have, g of pi over 3 is equal to co -secant, pi over 3, which will get us, let's see, our co -sacent...