00:01
Okay, so we know that w0 is equal to 1 .0504 times 10 to the fifth.
00:15
So if we take w0 and substitute in values, to the equation, we get 1 over the square root ion plus ion times r times r times r.
00:51
Times r over r, which equals to 1 .025 times 10 to the fifth equals to 1 over ion times r, where r is equal to 0 .975 .0 .k.
01:21
Holmes.
01:23
Then you substitute the resistances in, or you know, the ion f minus 0 .0 .003 f.
01:41
So you do the transfer fraction, where you have w over alpha, which equals to 2 ,700 ,860.
01:59
So then you take that alpha is equal q, actually, not alpha q, is equal to negative 1 times 1.
02:17
0 .025 times 10 to the fifth, where q is equal to 3 .88.
02:33
Then we get that 368 is equal to rx times r2 over r1, r3, r5, and then we substitute in our values...