00:01
Hi, so this problem here wants us to consider the electron geometry and hybridization at this atom.
00:10
So this falls in line with vsepr theory.
00:17
And it's something that most people have to memorize because there are a lot of things to remember.
00:22
But for this problem, we can kind of take it step by step and work our answer from the very basics.
00:31
So this question here, as long as we know the number of electron domains, then we can solve the entire problem.
00:45
And what i mean by electron domains is that for every loan pair or for every bond can be single, double, doesn't matter.
01:02
And double and triple bonds, each count as one.
01:06
One electron domain, then you count all of these up around the atom that you're looking at, and you get to your total number of electron domains, which will give you the information that you need to solve the electron geometry and the hybridization of the atom.
01:27
So here, we can see that we have one, two, three, and four electron domains.
01:37
And what this means is we can first try to solve with the hybridization of the atom.
01:43
And hybridization, what i like to think of it or how i like to remember it is it's always going to be in the form spx.
01:54
All right.
01:55
So we have one s orbital and some x number of p orbitals that we combine to create a hybrid.
02:07
And the golden rule is to remember that you always have.
02:10
Have x plus one hybrid orbitals total.
02:15
And this x plus one number should be equal to your number of electron domains.
02:21
Because each electron domain, remember, because it's a home for an electron, or home for a pair of electrons, it's going to need an orbital to house them.
02:34
So your total number of orbitals should be equal to four.
02:37
This means that your x should be of course, 4 equals x plus 1, x equals 3.
02:46
And that means that we can immediately eliminate b here, because that is sp2 hybridized.
02:53
We have an sp3 hybridized nitrogen.
02:57
Now we have to do is solve for the electron geometry.
03:02
And to do this, we don't even need to know the hybridization.
03:07
We need to focus on the number of electron domains.
03:11
And the way i think about this is, whenever you have four sites of negative charge, they all want to repel each other...