Consider the nuclide iron-56 (^56Fe).
(a) How many protons does it have?
protons
(b) How many neutrons does it have?
neutrons
(c) The mass of ^56Fe in atomic mass units is 55.934942 u. (Note this is the mass of the entire atom, not just the nucleus.) This mass is lower than the total mass of its constituent protons, neutrons, and electrons. Find the difference, in atomic mass units, between the total mass of the constituent particles and the actual mass of the nuclide. (This is sometimes called the "mass defect.") The mass of a proton is 1.007276 u, the mass of a neutron is 1.008665 u, and the mass of an electron is 5.486 Ă— 10^-4 u. (Round your answer to at least four decimal places.) u
(d) Since, according to special relativity theory, mass and energy are "equivalent," the mass defect, or "missing" mass found in part (c), is a measurement of the energy it would take to break the bound ^56Fe atom into its constituent particles. In other words, it is equivalent to the binding energy. Using the result of part (c), find the binding energy per nucleon, Eb/A, for ^56Fe in units of MeV. (Round your answer to at least two decimal places.) MeV