00:01
Hello students, here we have an ideal op -amp that has the input voltages va and output voltages v0.
00:07
So here we have to write down the current value of i3.
00:13
So here first we have to write the current value of i3.
00:21
So here we are using an ideal op -amp so current cannot flow through the input terminals because the input impedance is high.
00:37
Input impedance is high.
00:47
So i3 equal to 0 and in section 2 we have to calculate the input voltage that in the inverting terminal.
01:11
So here the current passing through the terminals are 0 so voltage in the input terminals are also 0.
01:37
Voltage in input terminals are 0.
01:50
So here we can write the input voltage v1 that is equal to 0 and in third we have to write down the output voltage equation.
02:07
So here we know that the input current i3 and i3 equal to 0 and so we can write i1 that is current passing through the r1 that is equal to the input current.
02:42
So here we can write down the voltages v1 and v2 are 0.
03:02
We can write vi equal to ifri and minus v0 equal to ifrf.
03:20
So here dividing these equations we will get minus v0 divided by vi that is equal to ifrf divided by ifri.
03:33
So that is equal to v0 by vi that is equal to rf divided by ri...