Consider the physical quantities s, v, a, and t with dimensions [s] = L, [v] = LT−1, [a] = LT−2, and [t] = T. Determine whether each of the following equations is dimensionally consistent. v = st a^2 = 2vs + t ast = v/t v = st + at^2
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The dimensional formula for velocity \(v\) is \(LT^{-1}\), and the dimensional formula for displacement \(s\) and time \(t\) are both \(L\). Since the dimensions on both sides of the equation are not equal, this equation is dimensionally inconsistent. ** Show more…
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