Question

Consider the probability distribution shown here. Complete parts a through c. \begin{tabular}{c|c c c c c c c c c} $x$ & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\ $P(x)$ & 0.01 & 0.06 & 0.09 & 0.14 & 0.34 & 0.19 & 0.09 & 0.06 & 0.02 \\ \end{tabular} a. Calculate $\mu$, $\sigma^2$, and $\sigma$. $\mu = \boxed{}$ (Round to two decimal places as needed.)

          Consider the probability distribution shown here. Complete parts a through c.
\begin{tabular}{c|c c c c c c c c c}
$x$ & -4 & -3 & -2 & -1 & 0 & 1 & 2 & 3 & 4 \\
$P(x)$ & 0.01 & 0.06 & 0.09 & 0.14 & 0.34 & 0.19 & 0.09 & 0.06 & 0.02 \\
\end{tabular}
a. Calculate $\mu$, $\sigma^2$, and $\sigma$.
$\mu = \boxed{}$ (Round to two decimal places as needed.)

Consider the probability distribution shown here. Complete parts a through c.

x -4 -3 -2 -1 0 1 2 3 4

P(x) 0.01 0.06 0.09 0.14 0.34 0.19 0.09 0.06 0.02

a. Calculate μ, σ^2, and σ.
μ = (Round to two decimal places as needed.)

Added by Mindy D.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Lien Le

09/23/2023

Step 1

Given that the sum of all probabilities must equal 1, we can calculate the missing probability for x = 1 by subtracting the sum of the probabilities for x = -4, -3, -2, and -1 from 1. p(x=1) = 1 - (0.01 + 0.06 + 0.09 + 0.14) = 0.70 Show more…

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Consider the probability distribution shown here. Complete parts a through c. able[[ able[[x Consider the probability distribution shown here. Complete parts a through c -4 -3 p(x) 0.01 0.06 -2 0.09 -1 0.14 1 2 0.09 0.19 3 0.06 0.02 .Calculate ,2,and =Round to two decimal places as needed.