00:02
Hello everyone we are going to understand this question here give it in the question given mass of pulley mass of pulley it is given mp and radius of pulley radius of pulley it is given r now let's draw the fvd here m2g is working vertically downward and reaction force is in upward direction that is represented by n tension force is represented by t2 in the string and pseudo acceleration that is m2 a because this block is moving with acceleration a acceleration a in downward so here weight of the block is m1 g in downward direction and tension t is in upward direction and net acceleration a is in downward direction.
01:28
Here, a is acceleration of the system.
01:36
Acceleration of the blocks.
01:44
Now, we can write as per newton's law of motion.
01:52
Here, balancing the equation, applying the force balance equation.
01:56
Here, m1g is working vertically downward and tension t1, t1 is in the string.
02:05
In vertically upward direction.
02:07
So net acceleration of the m1 block is a.
02:11
Let this is equation 1.
02:14
Now for block 2, tension in the string, t 2 is equal to t2 is equal to m2 into a.
02:27
Let this is equation 2.
02:31
And now applying the torque equation on the pulley...