00:03
As to consider an experiment where oxygen is collected over water at 40 degrees celsius.
00:22
We're told our total pressure is equal to 745 .0 mm hg.
00:35
We're told that we've collected 4 .70 liters of oxygen.
00:42
And we're told that our balanced chemical equation is two nickel oxides yields two nickel plus o2.
00:59
I'm going to look up my vapor pressure of water, so i'm going to look up my water pressure at 40 degrees.
01:12
So let me look up, vapor pressure, water, 40 dig c.
01:23
And at 40 i have 55 .3 tor.
01:32
55 .3 mhm hg.
01:37
I just looked that number up.
01:39
So if you've got a different table, verify that's the same.
01:42
So my p of o2 is going to equal my p total minus my p water.
01:51
That will equal 745 .0 mm.
01:54
Millimeters mercury minus 55 .3 millimeters mercury.
02:04
That'll be 745 minus 55 .3.
02:11
And that is 689 .m .hg.
02:21
That is my partial pressure of oxygen gas.
02:25
Next we're going to use the combined gas law to find n.
02:31
Rt...