00:01
Hello, the given problem is that the given reaction to n2 .05, to n2 .o5 in gases state gives 4 no2 in gases state plus o2 in gases state.
00:26
2 no 2 gives 4 an o2 plus o2.
00:30
So delta z is equal to delta h delta as minus.
00:42
T into delta s into delta s so delta h is equal to 4 into delta h f n o 2 plus delta h of o 2 minus 2 into delta h of 4 and 2 o 5 now put the value delta h f o 2 is equal to 4 into 4 into o 5 now put the value delta h h is equal to 4 into 0 5.
01:38
Delta hfo and o2 is equal to 33 .15 plus 0 minus delta hfo auto is equal to 0 minus 2 into delta h4 and 2 05 is equal to 11 .289.
02:20
After calculate this after calculate this we find delta h is equal to 110 .0 to 2 2 kilojoule temperature is equal to 25 degrees celsius.
02:41
So, degrees celsius is converted into kelvin, added to 73 kelvin, is equal to 298 kelvin.
02:57
The temperature is 298 kelvin.
03:02
Temperature is comes out 298 kelvin.
03:08
And delta h is equal to 110 .0 .0 .7.
03:14
Sorry, 110 .0 to kilojoules.
03:18
Now delta s is equal to formula of delta s is equal to delta s is equal to 4 into s node of no2 plus s node of o2 minus 2 into s node of n2 05.
03:43
Now delta s is equal to 4 into value of s node of n2 is equal to 2 33...