00:01
9 .35 grams of nitrogen gas reacting with 1 .17 grams of hydrogen gas.
00:07
And i've written the balanced chemical equation.
00:10
We are asked to find the maximum of nh4 that we can form in grams, the formula of the limiting reagent, and the mass of the excess that remains after reaction.
01:05
So what we're going to do is i think i'll just go to, mass of ammonia that can be formed because that'll give me two answers right away.
01:15
I'm going to start with 9 .35 grams of nitrogen.
01:25
We'll be doing a mass mass calculation with 20 .02 grams of n2 per mole of n2.
01:36
I will use a 1 to 2 mole ratio as per our balanced chemical equation for n2 to nh3.
01:46
Then i'll be using 17 .03 grams of nh3 per mole of nh3.
01:57
This will give me the theoretical yield for nh3, 9 .35 times 2 times 17 .03 divided by 28 .02.
02:17
And that would give me a theoretically yield of 11 .4 grams of nh3.
02:36
Okay, now my other substance, let's just switch colors for fun.
02:42
I have 1 .17 grams of hydrogen, and i'm going to do a similar calculation.
02:52
But of course, i'll use 2 .02 grams of hydrogen per mole as my molar mass, and a 3 to 2 mole ratio of hydrogen gas to ammonia.
03:10
My last part will still be 17 .03 grams of nh3 per...