Consider the reaction between acetylene, C 2H 2, and oxygen in a welding torch: 2C 2H 2( g) + 5O 2( g) → 4CO 2( g) + 2H 2O( g) If 5.4 moles of acetylene react with sufficient oxygen, how many grams of CO 2 should form?
Added by Mary H.
Step 1
The equation shows that 2 moles of C₂H₂ produce 4 moles of CO₂. Therefore, the molar ratio of C₂H₂ to CO₂ is 2:4, which simplifies to 1:2. Show more…
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Consider the reaction between acetylene, C2H2, and a welding torch: 2C2H2(g) + 5O2(g) --> 4CO2(g) + 2H2O(g). If 5.4 moles of acetylene react with sufficient oxygen, how many grams of CO2 should form?
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Acetylene (C2H2) gas is often used in welding torches because of the very high heat produced when it reacts with oxygen (O2) gas, producing carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 0.055 mol of acetylene. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
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Acetylene (C2H2) gas is often used in welding torches because of the very high heat produced when it reacts with oxygen (O2) gas, producing carbon dioxide gas and water vapor. Calculate the moles of carbon dioxide produced by the reaction of 0.050 mol of acetylene. Be sure your answer has a unit symbol, if necessary, and round it to the correct number of significant digits.
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