Consider the reaction: CaCl2(s) + 2H2O(g) <---> CaCl2•2H2O(s) The equilibrium constant for the reaction as written is: k = [CaCl2 . 2H2O]/[CaCl2][H2O]^2 k = 1 / [H2O]^2 k = 1 / 2[H2O] k = [H2O]^2 k = [CaCl2 . 2H2O]/[H2O]^2
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In this case, the reaction is: CaCl2(s) + 2H2O(g) ↔ CaCl2·2H2O(s) The equilibrium constant expression for this reaction would be: K = [CaCl2·2H2O] / ([CaCl2][H2O]^2) Show more…
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