Question

Consider the reaction of 75.0 mL of 0.350 M C₅H₅N (Kb = 1.7 x 10⁻⁹) with 100.0 mL of 0.405 M HCl. How many moles of H⁺ would be present if 100.0 mL of H⁺ were added?

Name: consider the reaction of 750 ml of 0350 m c5h5n kb 17 x 109 with 1000 ml of 0405 m hcl how many moles of h would be present if 1000 ml of h were added 88715
Uploaded: 2023-09-10T09:14:13-08:00
Duration: 1 min 5 s
Channel: Adi S
Description: consider the reaction of 750 ml of 0350 m c5h5n kb 17 x 109 with 1000 ml of 0405 m hcl how many moles of h would be present if 1000 ml of h were added 88715

          Consider the reaction of 75.0 mL of 0.350 M C₅H₅N (Kb = 1.7 x 10⁻⁹) with 100.0 mL of 0.405 M HCl. How many moles of H⁺ would be present if 100.0 mL of H⁺ were added?

Added by Olivia F.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Adi S

09/10/2023

Step 1

First, we need to find the initial moles of C₅H₅N and HCl. moles of C₅H₅N = (0.350 mol/L) * (0.075 L) = 0.02625 mol moles of HCl = (0.405 mol/L) * (0.100 L) = 0.0405 mol Show more…

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Consider the reaction of 75.0 mL of 0.350 M C₅H₅N (Kb = 1.7 x 10⁻⁹) with 100.0 mL of 0.405 M HCl. How many moles of H⁺ would be present if 100.0 mL of H⁺ were added?