Consider the reaction. H CH3 C=C + H-Cl: H3C CH3 H :Cl: H3C-C-C-CH3 H CH3 Add curved arrows for the first step. Draw both the organic and inorganic intermediate species. Include nonbonding electrons and charges, where applicable. Include hydrogen atoms.
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The lone pair of electrons on the chlorine atom attacks the hydrogen atom in the hydrogen chloride molecule, forming a new bond and breaking the H-Cl bond. ** Show more…
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Consider the reaction. Add curved arrows for the first step. Draw both the organic and inorganic intermediate species. Include nonbonding electrons and charges, where applicable. Include hydrogen atoms.
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Consider the reaction. Add curved arrows for the first step. Draw both the organic and inorganic intermediate species. Include nonbonding electrons and charges, where applicable.
Dr. Satish I.
$\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CO} \quad \frac{\mathrm{NaCN}}{(\mathrm{HCl})} \rightarrow \mathrm{A} \stackrel{\mathrm{H}_{3} \mathrm{O}^{+}}{\longrightarrow} \mathrm{B}$ in the above sequence of reactions $\mathrm{A}$ and $\mathrm{B}$ are (a) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHCOOH}$ (b) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH})_{2}$ (c) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{COOH}$ (d) $\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}(\mathrm{OH}) \mathrm{CN},\left(\mathrm{CH}_{3}\right)_{2} \mathrm{C}=\mathrm{O}$
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