0:00
Hello students.
00:01
So in this question we are given a simply supported beam drawn in the form of this way with uniform distributed load on the beam as three kips for feet.
00:15
Three kips per feet.
00:19
We are given two supports here.
00:22
This support and this support.
00:25
The length of the support from the outer end given is three feet and length of this support from the left.
00:33
And given is 2 feet we have to find the point where the bending moment is maximum from definition we know the bending moment is maximum okay the point where the bending moment is maximum at that point the shear force is zero or the share force changes the sign so we'll be finding the point where the share force is zero so let us take let us take the this point as the point where with reaction r1 and this point with reaction r2.
01:05
So r1 plus r2 will be equal to three times the total length of the beam that is so the distance between the two supports is 10 so the total length of the beam is 10 plus 2 plus 3 that is 15 so r1 plus r2 is 45 now we'll take the moment about the centroid will be taking the moment about the centroid to get the second excretion.
01:38
The centroid will be at the center, that is, it is at a distance of 7 .5 from either sides.
01:52
So, r1, anti -clockwise moment will be equals to the clockwise moment, r1 into 7 .5 minus 2, that is 7 .5 minus 2.
02:04
So this length will be 7 .5 minus 2 is equal to r2 into 7 .5 minus 3.
02:17
So r1 into 5 .5 is equal to r2 into 4 .5.
02:26
So from here we'll be finding the value of r1.
02:30
So r2 is equals to r1 into 5 .5 by 4 .5.
02:37
So this is the second equation.
02:39
And this is the first equation...