00:01
In this question we have given the system and the suspended block has a mass of 1 .5 kilogram.
00:05
The system is released from the rest and the block descends as the wheel rotates on a frictionless axle.
00:13
As the wheel is rotating the tension in the light wire is 9 newton, then we have to find the kinetic energy of the wheel 2 second after the system is released.
00:23
So first we have to find the acceleration of the block.
00:27
So using newton's second law of motion, we can say that net force is equal to mass into acceleration.
00:47
So the net force acting downward is mg minus tension in the string that is equals to mass into acceleration.
00:55
So acceleration will be, that is mass is 1 .5 into 9 .8 minus tension is 9 newton upon 1 .5 and that will come.
01:06
Comes out 3 .8 into 3 .8 meter per second square.
01:12
This is the acceleration of the block.
01:15
Now, if we calculate the distance traveled in time 2 second, so h is half 80 square.
01:30
So we can say this is 1 by 2 into acceleration is 3 .8 into time is 2 square...