00:01
This problem deals with evaluating functions given certain values for your variables, in this case, x within your function.
00:10
So my function, g of x is equal to x squared plus 3x, is a quadratic function, and i'm asked to determine g of 2, i'm asked to determine g of negative 2, and i'm asked to determine g of 0.
00:28
So we're going to plug in, in this case, the value of two for everywhere you see an x.
00:35
So i've got x squared and i've got 3x.
00:37
Now, remember what x squared means.
00:40
X squared is just x times itself, x times x.
00:43
So a number squared is a number times itself.
00:46
And then 3x is equal to 3 multiplied by x.
00:51
So that's important to remember.
00:53
We also need to think about our order of operations.
00:55
So we'll need to think about using either bedmass or pemdas, whatever you're familiar with, while solving these because we'll have more than one operation to solve.
01:09
So g of 2 means i'm going to substitute 2 in for x, wherever i see an x, and let's start solving this now.
01:19
So according to bedmass and pemdast, i'm going to do the exponent first.
01:22
So 2 squared is equal to 4.
01:25
And then i need to multiply three times two next.
01:31
So multiply three times two next, which gives me six.
01:37
So it becomes four plus six, which means our answer is equal to ten.
01:42
We just add those up.
01:43
So g of two is equal to ten...