00:01
In this problem, we're asked to calculate the ph at the equivalence point of the information that i've written right here.
00:08
So first of all, just because we should, let's jot down real quickly our chemical reaction.
00:18
So we can see this is a bunch of zeros here.
00:23
N -a -c -l -o plus h2o.
00:30
Okay, so we can see all of our coefficients are one.
00:32
And our moles of hclo will be equal to 170 milliliters.
00:45
And let's convert milliliters to liters.
00:56
Multiply the molarity by 0 .5682 moles per liter.
01:05
And this will equal 0 .17 times 0 .5682.
01:21
And this will be 0 .096594 moles of hclo.
01:33
So i will need to have, i need same moles of koh to neutralize.
01:46
So 0 .096594 moles of naoh will give me 0 .5003 moles per liter.
02:20
And this will give me point o or number of my calculator.
02:23
I should just do that.
02:24
Second answer divided by 0 .5003 and that will be 0 .19307 liters of naoh.
02:44
And that is a little less concentrated so that should sounds right to me.
02:50
My total volume of my solutions will be 0 .1700 liters plus 0 .19307 liters.
03:08
Equal number of my calculator plus 0 .17 is 0 .36307 liters.
03:19
That's how many solutions i have.
03:21
That's how much i have.
03:27
Okay, now my ocl minus concentration is going to be equal to my ocl minus concentration.
03:56
Concentration will be equal to my moles divided by 0 .36307 liters is 0 .266047.
04:40
Did i get a number mixed up here? this is going to give me an extremely high ph...