Question

Consider the vectors $f$ and $g$ with the given inner product.\\ $f(x) = 3x^3$, $g(x) = 4x^4$, $(f, g) = \int_{-1}^{1} f(x)g(x) dx$\ Find the lengths of $f$ and $g$ and their inner product.\ $||f|| = $\\ $||g|| = $\\ $(f, g) = $\\ Let $\theta$ be the angle between the vectors. Find $cos(\theta)$.\ $cos(\theta) = $\\ Find the angle $\theta$ between the vectors.\ $f(x) = 3x^3$, $g(x) = 4x^4$, $(f, g) = \int_{-1}^{1} f(x)g(x) dx$\ $\theta = $ radians

          Consider the vectors $f$ and $g$ with the given inner product.\\
$f(x) = 3x^3$, $g(x) = 4x^4$, $(f, g) = \int_{-1}^{1} f(x)g(x) dx$\
Find the lengths of $f$ and $g$ and their inner product.\
$||f|| = $\\
$||g|| = $\\
$(f, g) = $\\
Let $\theta$ be the angle between the vectors. Find $cos(\theta)$.\
$cos(\theta) = $\\
Find the angle $\theta$ between the vectors.\
$f(x) = 3x^3$, $g(x) = 4x^4$, $(f, g) = \int_{-1}^{1} f(x)g(x) dx$\
$\theta = $ radians

Consider the vectors f and g with the given inner product.

f(x) = 3x^3, g(x) = 4x^4, (f, g) = ∫-1^1 f(x)g(x) dxFind the lengths of f and g and their inner product.||f|| =

||g|| =

(f, g) =

Let θ be the angle between the vectors. Find cos(θ).cos(θ) =

Find the angle θ between the vectors.f(x) = 3x^3, g(x) = 4x^4, (f, g) = ∫-1^1 f(x)g(x) dxθ = radians

Added by Barry I.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Leslie Deeb

Step 1

Find the lengths of f and g: The length of a vector f is denoted as ||f|| and is calculated using the formula ||f|| = sqrt(f · f). In this case, we have f · f = 6x(x), so ||f|| = sqrt(6x(x)) = sqrt(6x^2) = sqrt(6)x. Similarly, the length of vector g is ||g|| = Show more…

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Consider the vectors f and g with the given inner product. f = 3, g = 4, f Â· g = 6x(x) Find the lengths of f and g and their inner product. = 10I ||f|| = 1 = 3 ||g|| = 1 = 4 Let Î¸ be the angle between the vectors. Find cos(Î¸) cos = Find the angle between the vectors xpxb(x = 6, xb = xbxE = x) radians