Question

Consider two large isothermal plates separated by a 2-mm thick oil film. The upper plate moves at a constant velocity of 12 m/s, while the lower plate is stationary. Both plates are maintained at 20°C. Determine the maximum temperature in the oil. Properties: k = 0.145 W/mK, u = 0.8 kg/ms, μ = 0.8 Ns/m^2.

          Consider two large isothermal plates separated by a 2-mm thick oil film. The upper plate moves at a constant velocity of 12 m/s, while the lower plate is stationary. Both plates are maintained at 20°C. Determine the maximum temperature in the oil. Properties: k = 0.145 W/mK, u = 0.8 kg/ms, μ = 0.8 Ns/m^2.
        
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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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Consider two large isothermal plates separated by a 2-mm thick oil film. The upper plate moves at a constant velocity of 12 m/s, while the lower plate is stationary. Both plates are maintained at 20°C. Determine the maximum temperature in the oil. Properties: k = 0.145 W/mK, u = 0.8 kg/ms, μ = 0.8 Ns/m^2.
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Transcript

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00:02 Hi, let flow direction be x.
00:06 For parallel flow v is equal to 0.
00:09 Continuity equation is dou u by dou x plus dou v by dou y is equal to 0.
00:19 That is dou u by dou x is equal to 0 which implies u is equal to u of y.
00:30 That is dou p by dou x is equal to 0 where x is the momentum.
00:37 Thus p into u of dou u by dou x plus v into dou u by dou y is equal to mu into dou square u by dou y square minus dou p by dou x which implies dou square u by dou y square is equal to 0.
01:03 On integrating twice we will obtain u of y is equal to c1 y plus c2.
01:15 Applying boundary conditions u of 0 is equal to 0 and u of l is equal to v.
01:24 Thus u of y is equal to y by l into p which is the velocity distribution.
01:32 Taking energy 0 is equal to k into dou square t by dou y square plus mu into dou y dou u by dou y the whole square which is equal to k into d square dt by dou y square is equal to minus mu into dou u by dou y which is written as k into dou square t by dou y square.
02:09 Is equal to minus mu into v by l the whole square...
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